PAS MATEMATIKA BLOG: April 2020

$\begin{array}{ll}\\ 1.&\textrm{Diketahui himpunan pasangan bilangan berurutan dari sebuah relasi}\\ &\left \{ (2,3).(1,4),(2,5),(3,5) \right \}.\: \textrm{Daerah kawandari relasi tersebut adalah}....\\ &\textrm{A}.\quad \left \{ 1,2,3 \right \}\\ &\textrm{B}.\quad \left \{ 3,4,5 \right \}\\ &\textrm{C}.\quad \left \{ 1,2,3,4,5 \right \}\\ &\textrm{D}.\quad \textrm{himpunan bilangan bulat}\\ &\textrm{E}.\quad \textrm{himpunan bilangan asli}\\\\ &\textrm{Jawab}:\qquad \textbf{B}\\ &\begin{aligned}\textrm{Daerah kawan}&=\textrm{daerah kodomain fungsi}\\ K_{f}&=\left \{ 3,4,5 \right \} \end{aligned} \end{array}$

$\begin{array}{ll}\\ 2.&\textrm{Diketahui dua buah himpunan yaitu}\: A=\left \{ -4,-2,0,2,4 \right \}\\ &\textrm{dan}\: \: B=\left \{ -3,-2,-1,0,1,2,3 \right \}.\: \textrm{Himpunan pasangan terurut}\\ &\textrm{yang menunjukkan relasi \textbf{dua kali dari} adalah}....\\ &\textrm{A}.\quad \left \{ (-4,-3),(-2,-2),(0,0),(2,2),(4,3) \right \}\\ &\textrm{B}.\quad \left \{ (-4,-2),(-2,2),(0,0),(2,2),(4,2) \right \}\\ &\textrm{C}.\quad \left \{ (-4,-2),(-2,-1),(0,0),(2,1),(4,2) \right \}\\ &\textrm{D}.\quad \left \{ (-4,-2),(-2,-1),(2,1),(4,2) \right \}\\ &\textrm{E}.\quad \left \{ (-4,-2),(-2,-1),(0,1),(2,1),(4,-2) \right \}\\\\ &\textrm{Jawab}:\qquad \textbf{C}\\ &\begin{aligned}\textrm{Daerah Asal}&=\textrm{daerah domain fungsi}\\ D_{f}&=\left \{ -4,-2,0,2,4 \right \} &\textrm{cukup jelas} \end{aligned} \end{array}$

$\begin{array}{ll}\\ 3.&\textrm{Himpunan pasangan berurutan yang ditunjukkan oleh fungsi}\\ &f:x\rightarrow 2-(x+1)^{2} \: \: \textrm{dari domain}\: \: \left \{ -1,0,1,2 \right \}\: \: \textrm{adalah}....\\ &\textrm{A}.\quad \left \{ (-1,2),(0,3),(1,5),(2,7) \right \}\\ &\textrm{B}.\quad \left \{ (-1,2),(0,1),(1,-2),(2,-7) \right \}\\ &\textrm{C}.\quad \left \{ (-1,1),(0,-1),(1,-4),(2,7) \right \}\\ &\textrm{D}.\quad \left \{ (-1,0),(0,3),(1,-2),(2,7) \right \}\\ &\textrm{E}.\quad \left \{ (-1,0),(0,-4),(1,5),(2,-7) \right \}\\\\ &\textrm{Jawab}:\qquad \textbf{B}\\ &\begin{aligned}f:x\rightarrow &2-(x+1)^{2},\quad \textrm{ini artinya}\: \: f(x)=2-(x+1)^{2}\\ \textrm{untuk}&\\ f(x)&=2-(x+1)^{2}\\ \textrm{maka}&\\ f(-1)&=2-(-1+1)^{2}=2-0=2\\ f(0)&=2-(0+1)^{2}=2-1=1\\ f(1)&=2-(1+1)^{2}=2-4=-2\\ f(2)&=2-(2+1)^{2}=2-9=-7 \end{aligned} \end{array}$

PAS MATEMATIKA BLOG

Contoh Soal Mid Semester Genap Kelas X Matematika Wajib Materi Fungsi

LANJUTAN 2 CONTOH SOAL MID SEMESTER GENAP KELAS X MATERI VEKTOR