$\begin{array}{ll}\\ 11.&\textrm{Perhatikanlah ilustrasi grafik di bawah ini}\\ &\begin{aligned}\end{aligned}\end{array}$.
$.\quad\begin{array}{ll}\\ &\textrm{Persamaan yang memenuhi rumus tersebut }\\ &\textrm{adalah}\: ... .\\ &\begin{array}{llll}\\ \textrm{a}.&y=\left | -x-2 \right |\\ \textrm{b}.&y=-2x-4\\ \textrm{c}.&y=-\left | 2x-4 \right |\\ \textrm{d}.&y=\left | -2x-4 \right |\\ \textrm{e}.&y=\left | -2x+4 \right | \end{array}\\\\ &\textrm{Jawab}:\quad \color{red}\textbf{e}\\ &\begin{aligned}&\textrm{Dengan cara substitusi langsung kita}\\ & \textrm{akan mendapatkan}\\ &\bullet \quad \textrm{untuk}\: \: x=4\: \: \textrm{menyebabkan nilai}\: \: y=4\\ &\qquad \textrm{dan sampai langkah di sini hanya ada }\\ &\qquad \textrm{1 persamaan yang memenuhi yaitu}:\\ &\qquad y=\color{red}\left | -2x+4 \right | \end{aligned} \end{array}$.
$\begin{array}{lll}\\ 12.&\textrm{Gambarlah garfik untuk persamaan}\\ & \left | x \right |+\left | y \right |=4\\\\\\ &\textrm{Jawab}:\\ &\begin{aligned}&\textrm{Dari soal diketahui}\\ &\left | x \right |+\left | y \right |=4\\ &\textrm{maka untuk} \end{aligned}\\&\begin{array}{|cc|cc|}\hline x> 0\: ,\: y> 0&&&x> 0\: ,\: y<0\\\hline x+y=4&&&x+(-y)=4\\ &&&\\\hline &&&\\ x<0\: ,\: y> 0&&&x<0\: ,\: y<0\\\hline (-x)+y=4&&&(-x)+(-y)=4\\\hline \end{array} \end{array}$.
$.\quad\begin{array}{ll}\\ &\textrm{Perhatikanlah ilustrasinya grafik di bawah ini}\\ &\begin{aligned}\end{aligned}\end{array}$.
$\begin{array}{lll}\\ 13.&\textrm{Tentukanlah nilai}\: \: x\: \: \textrm{dan}\: \: y\\ & \textrm{yang memenuhi}\: \: x+\left | x \right |+y=5\\ & \textrm{dan}\: \: x+\left | y \right |-y=10\\\\ &\textrm{Jawab}:\\ &\begin{aligned}&\textrm{Diketahui bahwa}:\\ &\begin{aligned} &\left | x \right |+x+y=5\\ &\: \: \qquad \textrm{dan}\\ &x+\left | y \right |-y=10\\ & \end{aligned} \end{aligned} \end{array}$.
$.\: \quad\begin{aligned}\begin{aligned}&\textrm{untuk}:\: \: x> 0\: ,\: y> 0\quad \textbf{(kuadran I)}\\ &\begin{cases} \left | x \right |+x+y=5 & \Leftrightarrow (x)+x+y=5 \\ &\Leftrightarrow 2x+y=5\: (\textrm{ada})\\ x+\left | y \right |-y=10 & \Leftrightarrow x+(y)-y=10\\ &\Leftrightarrow x=10\: (\textrm{ada}) \end{cases}\\ &\textrm{untuk}:\: \: x<0\: ,\: y> 0\quad \textbf{(kuadran II)}\\ &\begin{cases} \left | x \right |+x+y=5 & \Leftrightarrow (-x)+x+y=5\\ &\Leftrightarrow y=5\: (\textrm{ada})\\ x+\left | y \right |-y=10 & \Leftrightarrow x+(y)-y=10\\ &\Leftrightarrow x=10\\ &\textbf{(tidak memenuhi)} \end{cases} \end{aligned} \end{aligned}$.
$.\: \quad\begin{aligned}\begin{aligned}&\textrm{untuk}:\: \: x<0\: ,\: y<0\quad \textbf{(kuadran III)}\\ &\begin{cases} \left | x \right |+x+y=5 & \Leftrightarrow (-x)+x+y=5\\ &\Leftrightarrow y=5\\ & \textbf{(tidak memenuhi)}\\ x+\left | y \right |-y=10 & \Leftrightarrow x+(-y)-y=10\\ &\Leftrightarrow x-2y=10\: (\textrm{ada}) \end{cases}\\ &\textrm{untuk}:\: \: x> 0\: ,\: y<0\quad \textbf{(kuadran IV)}\\ &\begin{cases} \left | x \right |+x+y=5 & \Leftrightarrow (x)+x+y=5\\ &\Leftrightarrow 2x+y=5\: (\textrm{ada})\\ x+\left | y \right |-y=10 & \Leftrightarrow x+(-y)-y=10\\ &\Leftrightarrow x-2y=10\: (\textrm{ada}) \end{cases} \end{aligned} \end{aligned}$.
$.\quad\begin{array}{ll}\\ &\textrm{Sebagai ilustrasinya, berikut grafiknya}\\ &\begin{aligned}\end{aligned}\end{array}$.
$\begin{array}{ll}\\ 14.&\textrm{Gambarlah grafik fungsi mutlak berikut}\\ &\textrm{a}.\quad y=\left | x-2 \right |\\ &\textrm{b}.\quad y=-\left | x-2 \right |\\ &\textrm{c}.\quad y=2+\left | x-2 \right |\\ &\textrm{d}.\quad y=2-\left | x-2 \right |\\ &\textrm{e}.\quad y=\left | 2+\left | x-2 \right | \right |\\ &\textrm{f}.\quad y=\left | 2-\left | x-2 \right | \right | \end{array}$.
$.\quad\begin{array}{ll}\\ &\textbf{Jawab}\quad :\\ &\textrm{Berikut ilustrasinya}\\ &\textrm{grafik dari soal}\: \: \textbf{a} \end{array}$.
$.\quad\begin{array}{ll}\\ &\textrm{Dan berikut ilustrasinya}\\ &\textrm{grafik dari soal}\: \: \textbf{b} \end{array}$.
$.\quad\begin{array}{ll}\\ &\textrm{Dan berikut pula ilustrasinya}\\ &\textrm{grafik dari soal}\: \: \textbf{c} \end{array}$.
$.\quad\begin{array}{ll}\\ &\textrm{Dan berikut pula ilustrasinya}\\ &\textrm{grafik dari soal}\: \: \textbf{d} \end{array}$.
$.\quad\begin{array}{ll}\\ &\textrm{Dan sebagai ilustrasinya}\\ &\textrm{lihat soal no}\: \: \textbf{c} \end{array}$.
$.\quad\begin{array}{ll}\\ &\textrm{Dan terakhir berikut ilustrasinya}\\ &\textrm{grafik dari soal}\: \: \textbf{f} \end{array}$.
$\begin{array}{ll}\\ 15.&\textrm{Penyelesaian yang memenuhi untuk}\\ & \left | 3x-(4x-7) \right |=6\: \: \textrm{adalah}... .\\ &\begin{array}{llllll}\\ \textrm{a}.&\left \{ -13,-1 \right \}&&&\textrm{d}.&\left \{ -13,1 \right \}\\ \textrm{b}.&\left \{ -1,13 \right \}&\textrm{c}.&\left \{ 1,13 \right \}&\textrm{e}.&\left \{ 13 \right \} \end{array}\\\\ &\textrm{Jawab}:\quad \color{red}\textbf{c}\\ &\begin{aligned}\left | 3x-(4x-7) \right |&=6\\ \left | 3x-4x+7 \right |&=6\\ \left | -x+7 \right |&=6\\ \left ( -x+7 \right )&=\pm 6\\ -x+7&=\begin{cases} 6 \Leftrightarrow -x=6-7\Leftrightarrow x=\color{red}1\\\\ -6\Leftrightarrow -x=-6-7\Leftrightarrow x=\color{red}13 \end{cases} \end{aligned} \end{array}$.
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